3x^2-3(x-4)=7x+2

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Solution for 3x^2-3(x-4)=7x+2 equation: 



3x^2-3(x-4)=7x+2

We move all terms to the left:

3x^2-3(x-4)-(7x+2)=0

We multiply parentheses

3x^2-3x-(7x+2)+12=0

We get rid of parentheses

3x^2-3x-7x-2+12=0

We add all the numbers together, and all the variables

3x^2-10x+10=0

a = 3; b = -10; c = +10;
Δ = b2-4ac
Δ = -102-4·3·10
Δ = -20
Delta is less than zero, so there is no solution for the equation

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